Pi is an irrational number. This means that its digits continue indefinitely without ever repeating. Every possible finite combination of digits is therefore contained therein. This would technically include a digital representation of every possible copyrighted work.
Does this constitute prior art?
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data Foo = Bar { val :: Int } | Baz { val :: Int }
is valid #Haskell. I wouldn't have thought you could define
val
twice like that.
I have a messenger bag that I typically carry around with me. Sometimes things go in there and I forget about them.
Katy was looking for something and discovered that for some reason I had put our marriage certificate in there. The last time I needed the physical certificate was years ago, so it must've been sitting in there and I've just been carrying it around with me unknowingly for quite some time.
I imagine I should probably find a better place for it.
I should probably also go through it to see what else I've put in there and forgotten about.
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Ep. 320 Trapped in Treatment - The Troubled Teen Industry - Episode 156 Remastered
Remastered: Trapped In Treatment is a new docu-style podcast series from Paris Hilton & Warner Bros. Unscripted TV in Association With Telepictures, and iHeSpreaker
I'm an idiot.
I was trying to install #Haskell on a machine and thought the installer was taking a really long time. In my defense, the last line of text was:
Installation may take a while.
It sat at this stage for over an hour while I did other stuff, because I hadn't bothered to read the previous line:
Press ENTER to proceed or ctrl-c to abort.
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hlint
is a great tool for pointing out where your code can be improved, but sometimes its suggestions are... interesting. Case in point, it just recommended changingmap (\(a, b) -> {- ...stuff... -}) $ zip as bs
to
zipWith (curry (\(a, b) -> {- ...stuff... -})) as bs
instead of
zipWith (\a b -> {- ...stuff... -}) as bs
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Ep. 319 ISKCON and other spiritual groups - Episode 150 Part 2 Remastered
In this remastered episode I chat with someone who has experienced The International Society for Krishna Consciousness. Michael gives a deep dive into many typeSpreaker
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Got an oscilloscope as a late birthday present. One of the features listed on the box is "firmware updates".
Why on earth would an oscilloscope need firmware updates? It's an oscilloscope.
Next up: learn how to use an oscilloscope. 🙃
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We have to order @Benny's food from the vet because he's on a prescription diet. Tried using their on-line ordering option. We ordered his food a week ago. It just arrived this morning.
We just got tracking now.
Thanks. That's helpful.
𝕕𝕚𝕒𝕟𝕖𝕒 🏳️⚧️🦋 likes this.
Brief outage because the new server accidentally came disconnected from power.
Everything's back up. Anxiety levels returning to normal.
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Can anyone in Waterloo region recommend a place (such as a coffee shop) where one can just sit down with a book for a while? I don't mind if I have to buy a coffee or something. Just looking for a change of scenery.
There's always the library, but the nearest one to me is in a high school, and I feel weird about loitering around there.
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"Another person who won't debate me because they can't handle my arguments."
No friend, another person who won't debate you because you're freaking exhausting and I just can't be bothered... but you keep telling yourself that.
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Khurram Wadee
in reply to Jonathan Lamothe • • •Bob Jonkman
in reply to Jonathan Lamothe • • •I'll bite, but not about the IP part.
Just because an irrational number's digits continue indefinitely without ever repeating, does that necessarily mean that it contains every arbitrary finite sequence of digits?
#Mathstodon
1/
Bob Jonkman
in reply to Bob Jonkman • • •Is there at least one finite sequence of digits that isn't represented in pi? If so, there are probably an infinite set of finite sequences of arbitrary numbers not represented in pi.
*something something* Cantor's infinite set of infinite sets...
#Mathstodon
2/
Bob Jonkman
in reply to Bob Jonkman • • •OTOH, if every finite sequence of arbitrary digits is represented in pi, then we should be able to find in pi a representation of, say, Euler's number to any given precision...
#Mathstodon
3/3 Enough for now. I don't have the math-fu to know if I'm being rational.
#BaDumTiss
Jonathan Lamothe
in reply to Bob Jonkman • •soaproot
in reply to Bob Jonkman • • •@bobjonkman No. Consider 1.0100100010000100001..... This is irrational but it doesn't contain any sequence of digits containing digits other than one or zero.
As for the irrational number pi, I think maybe it is unknown whether it contains all sequences of digits, but I don't know where to quickly check that.
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Jonathan Lamothe
in reply to soaproot • •Bob Jonkman reshared this.
Jonathan Lamothe
in reply to Jonathan Lamothe • •@soaproot ...though could it not then be argued that this number contains a binary encoding of all possible sequences?
Edit: actually, not necessarily.
Edit 2: Okay, I see the pattern now. Definitely not.
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